JPA 2에서 CriteriaQuery를 사용하여 결과를 계산하는 방법
나는 JPA 2에 익숙하지 않으며 CriteriaBuilder / CriteriaQuery API입니다.
CriteriaQuery의 결과를 실제로 검색하지 않고 계산하고 싶습니다. 가능합니까, 나는 그런 방법을 찾지 못했습니다, 유일한 방법은 이것을하는 것입니다 :
CriteriaBuilder cb = entityManager.getCriteriaBuilder();
CriteriaQuery<MyEntity> cq = cb
.createQuery(MyEntityclass);
// initialize predicates here
return entityManager.createQuery(cq).getResultList().size();
그리고 그것은 그것을하는 올바른 방법이 될 수 없습니다 ...
해결책이 있습니까?
유형의 쿼리 MyEntity
가을 반환 MyEntity
합니다. 에 대한 검색어를 원합니다 Long
.
CriteriaBuilder qb = entityManager.getCriteriaBuilder();
CriteriaQuery<Long> cq = qb.createQuery(Long.class);
cq.select(qb.count(cq.from(MyEntity.class)));
cq.where(/*your stuff*/);
return entityManager.createQuery(cq).getSingleResult();
분명히 예제에서 건너 뛴 제한 및 그룹화 등을 사용하여 식을 작성하고 싶을 것입니다.
cb.createQuery ()를 사용하여 이것을 정렬했습니다 (결과 유형 매개 변수없이).
public class Blah() {
CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();
CriteriaQuery query = criteriaBuilder.createQuery();
Root<Entity> root;
Predicate whereClause;
EntityManager entityManager;
Class<Entity> domainClass;
... Methods to create where clause ...
public Blah(EntityManager entityManager, Class<Entity> domainClass) {
this.entityManager = entityManager;
this.domainClass = domainClass;
criteriaBuilder = entityManager.getCriteriaBuilder();
query = criteriaBuilder.createQuery();
whereClause = criteriaBuilder.equal(criteriaBuilder.literal(1), 1);
root = query.from(domainClass);
}
public CriteriaQuery<Entity> getQuery() {
query.select(root);
query.where(whereClause);
return query;
}
public CriteriaQuery<Long> getQueryForCount() {
query.select(criteriaBuilder.count(root));
query.where(whereClause);
return query;
}
public List<Entity> list() {
TypedQuery<Entity> q = this.entityManager.createQuery(this.getQuery());
return q.getResultList();
}
public Long count() {
TypedQuery<Long> q = this.entityManager.createQuery(this.getQueryForCount());
return q.getSingleResult();
}
}
그것이 도움이되기를 바랍니다 :)
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<Long> cq = cb.createQuery(Long.class);
cq.select(cb.count(cq.from(MyEntity.class)));
return em.createQuery(cq).getSingleResult();
As others answers are correct, but too simple, so for completeness I'm presenting below code snippet to perform SELECT COUNT
on a sophisticated JPA Criteria query (with multiple joins, fetches, conditions).
It is slightly modified this answer.
public <T> long count(final CriteriaBuilder cb, final CriteriaQuery<T> selectQuery,
Root<T> root) {
CriteriaQuery<Long> query = createCountQuery(cb, selectQuery, root);
return this.entityManager.createQuery(query).getSingleResult();
}
private <T> CriteriaQuery<Long> createCountQuery(final CriteriaBuilder cb,
final CriteriaQuery<T> criteria, final Root<T> root) {
final CriteriaQuery<Long> countQuery = cb.createQuery(Long.class);
final Root<T> countRoot = countQuery.from(criteria.getResultType());
doJoins(root.getJoins(), countRoot);
doJoinsOnFetches(root.getFetches(), countRoot);
countQuery.select(cb.count(countRoot));
countQuery.where(criteria.getRestriction());
countRoot.alias(root.getAlias());
return countQuery.distinct(criteria.isDistinct());
}
@SuppressWarnings("unchecked")
private void doJoinsOnFetches(Set<? extends Fetch<?, ?>> joins, Root<?> root) {
doJoins((Set<? extends Join<?, ?>>) joins, root);
}
private void doJoins(Set<? extends Join<?, ?>> joins, Root<?> root) {
for (Join<?, ?> join : joins) {
Join<?, ?> joined = root.join(join.getAttribute().getName(), join.getJoinType());
joined.alias(join.getAlias());
doJoins(join.getJoins(), joined);
}
}
private void doJoins(Set<? extends Join<?, ?>> joins, Join<?, ?> root) {
for (Join<?, ?> join : joins) {
Join<?, ?> joined = root.join(join.getAttribute().getName(), join.getJoinType());
joined.alias(join.getAlias());
doJoins(join.getJoins(), joined);
}
}
Hope it saves somebody's time.
Because IMHO JPA Criteria API is not intuitive nor quite readable.
It is a bit tricky, depending on the JPA 2 implementation you use, this one works for EclipseLink 2.4.1, but doesn't for Hibernate, here a generic CriteriaQuery count for EclipseLink:
public static Long count(final EntityManager em, final CriteriaQuery<?> criteria)
{
final CriteriaBuilder builder=em.getCriteriaBuilder();
final CriteriaQuery<Long> countCriteria=builder.createQuery(Long.class);
countCriteria.select(builder.count(criteria.getRoots().iterator().next()));
final Predicate
groupRestriction=criteria.getGroupRestriction(),
fromRestriction=criteria.getRestriction();
if(groupRestriction != null){
countCriteria.having(groupRestriction);
}
if(fromRestriction != null){
countCriteria.where(fromRestriction);
}
countCriteria.groupBy(criteria.getGroupList());
countCriteria.distinct(criteria.isDistinct());
return em.createQuery(countCriteria).getSingleResult();
}
The other day I migrated from EclipseLink to Hibernate and had to change my count function to the following, so feel free to use either as this is a hard problem to solve, it might not work for your case, it has been in use since Hibernate 4.x, notice that I don't try to guess which is the root, instead I pass it from the query so problem solved, too many ambiguous corner cases to try to guess:
public static <T> long count(EntityManager em,Root<T> root,CriteriaQuery<T> criteria)
{
final CriteriaBuilder builder=em.getCriteriaBuilder();
final CriteriaQuery<Long> countCriteria=builder.createQuery(Long.class);
countCriteria.select(builder.count(root));
for(Root<?> fromRoot : criteria.getRoots()){
countCriteria.getRoots().add(fromRoot);
}
final Predicate whereRestriction=criteria.getRestriction();
if(whereRestriction!=null){
countCriteria.where(whereRestriction);
}
final Predicate groupRestriction=criteria.getGroupRestriction();
if(groupRestriction!=null){
countCriteria.having(groupRestriction);
}
countCriteria.groupBy(criteria.getGroupList());
countCriteria.distinct(criteria.isDistinct());
return em.createQuery(countCriteria).getSingleResult();
}
You can also use Projections:
ProjectionList projection = Projections.projectionList();
projection.add(Projections.rowCount());
criteria.setProjection(projection);
Long totalRows = (Long) criteria.list().get(0);
참고URL : https://stackoverflow.com/questions/2883887/in-jpa-2-using-a-criteriaquery-how-to-count-results
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