객체 속성으로 배열에서 객체 제거

객체 속성으로 배열에서 객체 제거

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var listToDelete = ['abc', 'efg'];

var arrayOfObjects = [{id:'abc',name:'oh'}, // delete me
                      {id:'efg',name:'em'}, // delete me
                      {id:'hij',name:'ge'}] // all that should remain

객체 속성을 일치시켜 배열에서 객체를 제거하려면 어떻게합니까?

기본 JavaScript 만 사용하십시오.

삭제 할 때마다 길이가 줄어들 기 때문에 스플 라이스를 사용하는 데 문제가 있습니다. Orignal 인덱스에서 복제 및 스 플라이 싱을 사용하면 여전히 길이가 줄어드는 문제가 있습니다.

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나는 당신 splice이 이와 같은 것을 사용 했다고 가정 합니까?

for (var i = 0; i < arrayOfObjects.length; i++) {
    var obj = arrayOfObjects[i];

    if (listToDelete.indexOf(obj.id) !== -1) {
        arrayOfObjects.splice(i, 1);
    }
}

버그를 해결하기 위해해야 ​​할 일은 i다음에 줄어드는 것 입니다. (뒤로 반복하는 것도 옵션입니다) :

for (var i = 0; i < arrayOfObjects.length; i++) {
    var obj = arrayOfObjects[i];

    if (listToDelete.indexOf(obj.id) !== -1) {
        arrayOfObjects.splice(i, 1);
        i--;
    }
}

선형 시간 삭제를 피하기 위해 배열 위에 유지 하려는 배열 요소를 작성할 수 있습니다 .

var end = 0;

for (var i = 0; i < arrayOfObjects.length; i++) {
    var obj = arrayOfObjects[i];

    if (listToDelete.indexOf(obj.id) === -1) {
        arrayOfObjects[end++] = obj;
    }
}

arrayOfObjects.length = end;

최신 런타임에서 선형 시간 조회를 피하기 위해 해시 세트를 사용할 수 있습니다.

const setToDelete = new Set(listToDelete);
let end = 0;

for (let i = 0; i < arrayOfObjects.length; i++) {
    const obj = arrayOfObjects[i];

    if (setToDelete.has(obj.id)) {
        arrayOfObjects[end++] = obj;
    }
}

arrayOfObjects.length = end;

좋은 기능으로 싸일 수 있습니다.

const filterInPlace = (array, predicate) => {
    let end = 0;

    for (let i = 0; i < array.length; i++) {
        const obj = array[i];

        if (predicate(obj)) {
            array[end++] = obj;
        }
    }

    array.length = end;
};

const toDelete = new Set(['abc', 'efg']);

const arrayOfObjects = [{id: 'abc', name: 'oh'},
                        {id: 'efg', name: 'em'},
                        {id: 'hij', name: 'ge'}];

filterInPlace(arrayOfObjects, obj => !toDelete.has(obj.id));
console.log(arrayOfObjects);

당신이 그 자리에 그것을 할 필요가 없다면, 그것은 Array#filter:

const toDelete = new Set(['abc', 'efg']);
const newArray = arrayOfObjects.filter(obj => !toDelete.has(obj.id));

---

You can remove an item by one of its properties without using any 3rd party libs like this:

var removeIndex = array.map(function(item) { return item.id; })
                       .indexOf("abc");

~removeIndex && array.splice(removeIndex, 1);

---

With lodash/underscore:

If you want to modify the existing array itself, then we have to use splice. Here is the little better/readable way using findWhere of underscore/lodash:

var items= [{id:'abc',name:'oh'}, // delete me
                  {id:'efg',name:'em'},
                  {id:'hij',name:'ge'}];

items.splice(_.indexOf(items, _.findWhere(items, { id : "abc"})), 1);

With ES5 or higher

(without lodash/underscore)

With ES5 onwards we have findIndex method on array, so its easy without lodash/underscore

items.splice(items.findIndex(function(i){
    return i.id === "abc";
}), 1);

(ES5 is supported in almost all morden browsers)

About findIndex, and its Browser compatibility

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findIndex works for modern browsers:

var myArr = [{id:'a'},{id:'myid'},{id:'c'}];
var index = arr.findIndex(function(o){
     return o.id === 'myid';
})
if (index !== -1) myArr.splice(index, 1);

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If you just want to remove it from the existing array and not create a new one, try:

var items = [{Id: 1},{Id: 2},{Id: 3}];
items.splice(_.indexOf(items, _.find(items, function (item) { return item.Id === 2; })), 1);

---

Only native JavaScript please.

As an alternative, more "functional" solution, working on ECMAScript 5, you could use:

var listToDelete = ['abc', 'efg'];
var arrayOfObjects = [{id:'abc',name:'oh'}, // delete me
                      {id:'efg',name:'em'}, // delete me
                      {id:'hij',name:'ge'}]; // all that should remain

arrayOfObjects.reduceRight(function(acc, obj, idx) {
    if (listToDelete.indexOf(obj.id) > -1)
        arrayOfObjects.splice(idx,1);
}, 0); // initial value set to avoid issues with the first item and
       // when the array is empty.

console.log(arrayOfObjects);
[ { id: 'hij', name: 'ge' } ]

According to the definition of 'Array.prototype.reduceRight' in ECMA-262:

reduceRight does not directly mutate the object on which it is called but the object may be mutated by the calls to callbackfn.

So this is a valid usage of reduceRight.

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Loop in reverse by decrementing i to avoid the problem:

for (var i = arrayOfObjects.length - 1; i >= 0; i--) {
    var obj = arrayOfObjects[i];

    if (listToDelete.indexOf(obj.id) !== -1) {
        arrayOfObjects.splice(i, 1);
    }
}

Or use filter:

var newArray = arrayOfObjects.filter(function(obj) {
    return listToDelete.indexOf(obj.id) === -1;
});

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Check this out using Set and ES6 filter.

  let result = arrayOfObjects.filter( el => (-1 == listToDelete.indexOf(el.id)) );
  console.log(result);

Here is JsFiddle: https://jsfiddle.net/jsq0a0p1/1/

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var arrayOfObjects = [{id:'abc',name:'oh'}, // delete me
                      {id:'efg',name:'em'}, // delete me
                      {id:'hij',name:'ge'}] // all that should remain

as per your answer will be like this. when you click some particular object send the index in the param for the delete me function. This simple code will work like charm.

function deleteme(i){
    if (i > -1) {
      arrayOfObjects.splice(i, 1);
    }
}

---

with filter & indexOf

withLodash = _.filter(arrayOfObjects, (obj) => (listToDelete.indexOf(obj.id) === -1));
withoutLodash = arrayOfObjects.filter(obj => listToDelete.indexOf(obj.id) === -1);

with filter & includes

withLodash = _.filter(arrayOfObjects, (obj) => (!listToDelete.includes(obj.id)))
withoutLodash = arrayOfObjects.filter(obj => !listToDelete.includes(obj.id));

---

To delete an object by it's id in given array;

const hero = [{'id' : 1, 'name' : 'hero1'}, {'id': 2, 'name' : 'hero2'}];
//remove hero1
const updatedHero = hero.filter(item => item.id !== 1);

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If you like short and self descriptive parameters or if you don't want to use splice and go with a straight forward filter or if you are simply a SQL person like me:

function removeFromArrayOfHash(p_array_of_hash, p_key, p_value_to_remove){
    return p_array_of_hash.filter((l_cur_row) => {return l_cur_row[p_key] != p_value_to_remove});
}

And a sample usage:

l_test_arr = 
[
    {
         post_id: 1,
        post_content: "Hey I am the first hash with id 1"
    },
    {
        post_id: 2,
        post_content: "This is item 2"
    },
    {
        post_id: 1,
        post_content: "And I am the second hash with id 1"
    },
    {
        post_id: 3,
        post_content: "This is item 3"
    },
 ];



 l_test_arr = removeFromArrayOfHash(l_test_arr, "post_id", 2); // gives both of the post_id 1 hashes and the post_id 3
 l_test_arr = removeFromArrayOfHash(l_test_arr, "post_id", 1); // gives only post_id 3 (since 1 was removed in previous line)

참고URL : https://stackoverflow.com/questions/16491758/remove-objects-from-array-by-object-property