Android 카메라 의도
인 텐트를 기본 카메라 애플리케이션에 푸시하여 사진을 찍고 저장하고 URI를 반환해야합니다. 이렇게 할 수있는 방법이 있습니까?
private static final int TAKE_PICTURE = 1;
private Uri imageUri;
public void takePhoto(View view) {
Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
File photo = new File(Environment.getExternalStorageDirectory(), "Pic.jpg");
intent.putExtra(MediaStore.EXTRA_OUTPUT,
Uri.fromFile(photo));
imageUri = Uri.fromFile(photo);
startActivityForResult(intent, TAKE_PICTURE);
}
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
switch (requestCode) {
case TAKE_PICTURE:
if (resultCode == Activity.RESULT_OK) {
Uri selectedImage = imageUri;
getContentResolver().notifyChange(selectedImage, null);
ImageView imageView = (ImageView) findViewById(R.id.ImageView);
ContentResolver cr = getContentResolver();
Bitmap bitmap;
try {
bitmap = android.provider.MediaStore.Images.Media
.getBitmap(cr, selectedImage);
imageView.setImageBitmap(bitmap);
Toast.makeText(this, selectedImage.toString(),
Toast.LENGTH_LONG).show();
} catch (Exception e) {
Toast.makeText(this, "Failed to load", Toast.LENGTH_SHORT)
.show();
Log.e("Camera", e.toString());
}
}
}
}
Intent intent = new Intent("android.media.action.IMAGE_CAPTURE");
startActivityForResult(intent, 0);
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
if (resultCode == Activity.RESULT_OK && requestCode == 0) {
String result = data.toURI();
// ...
}
}
이 작업을 수행하는 데 몇 시간이 걸렸습니다. 코드 는 약간의 차이가 있지만 거의 developer.android.com 에서 복사하여 붙여 넣은 것입니다.
에 대한이 권한을 요청하십시오 AndroidManifest.xml
.
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />
에서 다음 Activity
을 정의 하여 시작하십시오.
static final int REQUEST_IMAGE_CAPTURE = 1;
private Bitmap mImageBitmap;
private String mCurrentPhotoPath;
private ImageView mImageView;
그런 다음이 화재 Intent
에 onClick
:
Intent cameraIntent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
if (cameraIntent.resolveActivity(getPackageManager()) != null) {
// Create the File where the photo should go
File photoFile = null;
try {
photoFile = createImageFile();
} catch (IOException ex) {
// Error occurred while creating the File
Log.i(TAG, "IOException");
}
// Continue only if the File was successfully created
if (photoFile != null) {
cameraIntent.putExtra(MediaStore.EXTRA_OUTPUT, Uri.fromFile(photoFile));
startActivityForResult(cameraIntent, REQUEST_IMAGE_CAPTURE);
}
}
다음 지원 방법을 추가하십시오.
private File createImageFile() throws IOException {
// Create an image file name
String timeStamp = new SimpleDateFormat("yyyyMMdd_HHmmss").format(new Date());
String imageFileName = "JPEG_" + timeStamp + "_";
File storageDir = Environment.getExternalStoragePublicDirectory(
Environment.DIRECTORY_PICTURES);
File image = File.createTempFile(
imageFileName, // prefix
".jpg", // suffix
storageDir // directory
);
// Save a file: path for use with ACTION_VIEW intents
mCurrentPhotoPath = "file:" + image.getAbsolutePath();
return image;
}
그런 다음 결과를받습니다.
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
if (requestCode == REQUEST_IMAGE_CAPTURE && resultCode == RESULT_OK) {
try {
mImageBitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), Uri.parse(mCurrentPhotoPath));
mImageView.setImageBitmap(mImageBitmap);
} catch (IOException e) {
e.printStackTrace();
}
}
}
작동하게 만든 것은 MediaStore.Images.Media.getBitmap(this.getContentResolver(), Uri.parse(mCurrentPhotoPath))
이며 이는 developer.android.com 의 코드와 다릅니다 . 원래 코드는 나에게 FileNotFoundException
.
내가 찾은 다음을 시도해보십시오. 링크가 있습니다.
If your app targets M and above and declares as using the CAMERA permission which is not granted, then attempting to use this action will result in a SecurityException.
EasyImage.openCamera(Activity activity, int type);
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
EasyImage.handleActivityResult(requestCode, resultCode, data, this, new DefaultCallback() {
@Override
public void onImagePickerError(Exception e, EasyImage.ImageSource source, int type) {
//Some error handling
}
@Override
public void onImagesPicked(List<File> imagesFiles, EasyImage.ImageSource source, int type) {
//Handle the images
onPhotosReturned(imagesFiles);
}
});
}
I found a pretty simple way to do this. Use a button to open it using an on click
listener to start the function openc()
, like this:
String fileloc;
private void openc()
{
Intent takePictureIntent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
File f = null;
try
{
f = File.createTempFile("temppic",".jpg",getApplicationContext().getCacheDir());
if (takePictureIntent.resolveActivity(getPackageManager()) != null)
{
takePictureIntent.putExtra(MediaStore.EXTRA_OUTPUT,FileProvider.getUriForFile(profile.this, BuildConfig.APPLICATION_ID+".provider",f));
fileloc = Uri.fromFile(f)+"";
Log.d("texts", "openc: "+fileloc);
startActivityForResult(takePictureIntent, 3);
}
}
catch (IOException e)
{
e.printStackTrace();
}
}
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data)
{
super.onActivityResult(requestCode, resultCode, data);
if(requestCode == 3 && resultCode == RESULT_OK) {
Log.d("texts", "onActivityResult: "+fileloc);
// fileloc is the uri of the file so do whatever with it
}
}
You can do whatever you want with the uri
location string. For instance, I send it to an image cropper to crop the image.
try this code
Intent photo= new Intent("android.media.action.IMAGE_CAPTURE");
startActivityForResult(photo, CAMERA_PIC_REQUEST);
참고URL : https://stackoverflow.com/questions/2729267/android-camera-intent
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