PHP 디렉토리에있는 파일 수 계산

PHP 디렉토리에있는 파일 수 계산

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저는 약간 새로운 프로젝트를 진행하고 있습니다. 특정 디렉토리에 몇 개의 파일이 있는지 계산하도록 만드는 방법을 알고 싶었습니다.

<div id="header">
<?php 
    $dir = opendir('uploads/'); # This is the directory it will count from
    $i = 0; # Integer starts at 0 before counting

    # While false is not equal to the filedirectory
    while (false !== ($file = readdir($dir))) { 
        if (!in_array($file, array('.', '..') and !is_dir($file)) $i++;
    }

    echo "There were $i files"; # Prints out how many were in the directory
?>
</div>

이것이 내가 지금까지 (검색에서) 가진 것입니다. 그러나 제대로 나타나지 않습니까? 몇 가지 메모를 추가 했으므로 자유롭게 제거 할 수 있습니다. 가능한 한 최대한 이해할 수 있도록합니다.

더 많은 정보가 필요하거나이 내용을 충분히 설명하지 않은 것 같다면 언제든지 말씀해주십시오.

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다음을 수행 할 수 있습니다.

$fi = new FilesystemIterator(__DIR__, FilesystemIterator::SKIP_DOTS);
printf("There were %d Files", iterator_count($fi));

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다음과 같이 파일 수를 얻을 수 있습니다.

$directory = "/path/to/dir/";
$filecount = 0;
$files = glob($directory . "*");
if ($files){
 $filecount = count($files);
}
echo "There were $filecount files";

(가) 어디에 "*"당신이 좋아 원하는 경우 특정 파일 유형에 해당을 변경할 수 있습니다 "*.jpg"또는 당신은이 같은 여러 파일 형식을 할 수있는 :

glob($directory . "*.{jpg,png,gif}",GLOB_BRACE)

GLOB_BRACE'A', 'B'또는 'C'에 대한 매치 플래그 팽창 {A, B, C}

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다음이 있어야합니다.

<div id="header">
<?php 
    // integer starts at 0 before counting
    $i = 0; 
    $dir = 'uploads/';
    if ($handle = opendir($dir)) {
        while (($file = readdir($handle)) !== false){
            if (!in_array($file, array('.', '..')) && !is_dir($dir.$file)) 
                $i++;
        }
    }
    // prints out how many were in the directory
    echo "There were $i files";
?>
</div>

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이 시도.

// Directory
$directory = "/dir";

// Returns array of files
$files = scandir($directory);

// Count number of files and store them to variable..
$num_files = count($files)-2;

Not counting the '.' and '..'.

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Working Demo

<?php

$directory = "../images/team/harry/"; // dir location
if (glob($directory . "*.*") != false)
{
 $filecount = count(glob($directory . "*.*"));
 echo $filecount;
}
else
{
 echo 0;
}

?>

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Since I needed this too, I was curious as to which alternative was the fastest.

I found that -- if all you want is a file count -- Baba's solution is a lot faster than the others. I was quite surprised.

Try it out for yourself:

<?php
define('MYDIR', '...');

foreach (array(1, 2, 3) as $i)
{
    $t = microtime(true);
    $count = run($i);
    echo "$i: $count (".(microtime(true) - $t)." s)\n";
}

function run ($n)
{
    $func = "countFiles$n";
    $x = 0;
    for ($f = 0; $f < 5000; $f++)
        $x = $func();
    return $x;
}

function countFiles1 ()
{
    $dir = opendir(MYDIR);
    $c = 0;
    while (($file = readdir($dir)) !== false)
        if (!in_array($file, array('.', '..')))
            $c++;
    closedir($dir);
    return $c;
}

function countFiles2 ()
{
    chdir(MYDIR);
    return count(glob("*"));
}

function countFiles3 () // Fastest method
{
    $f = new FilesystemIterator(MYDIR, FilesystemIterator::SKIP_DOTS);
    return iterator_count($f);
}
?>

Test run: (obviously, glob() doesn't count dot-files)

1: 99 (0.4815571308136 s)
2: 98 (0.96104407310486 s)
3: 99 (0.26513481140137 s)

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The best answer in my opinion:

$num = count(glob("/exact/path/to/files/" . "*"));
echo $num;

• It doesnt counts . and ..
• Its a one liner
• Im proud of it

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I use this:

count(glob("yourdir/*",GLOB_BRACE))

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<?php echo(count(array_slice(scandir($directory),2))); ?>

array_slice works similary like substr function, only it works with arrays.

For example, this would chop out first two array keys from array:

$key_zero_one = array_slice($someArray, 0, 2);

And if You ommit the first parameter, like in first example, array will not contain first two key/value pairs *('.' and '..').

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Maybe usefull to someone. On a Windows system, you can let Windows do the job by calling the dir-command. I use an absolute path, like E:/mydir/mysubdir.

<?php 
$mydir='E:/mydir/mysubdir';
$dir=str_replace('/','\\',$mydir);
$total = exec('dir '.$dir.' /b/a-d | find /v /c "::"');

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$it = new filesystemiterator(dirname("Enter directory here"));
printf("There were %d Files", iterator_count($it));
echo("<br/>");
    foreach ($it as $fileinfo) {
        echo $fileinfo->getFilename() . "<br/>\n";
    } 

This should work enter the directory in dirname. and let the magic happen.

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$files = glob('uploads/*');
$count = 0;
$totalCount = 0;
$subFileCount = 0;
foreach ($files as $file) 
{  
    global $count, $totalCount;
    if(is_dir($file))
    {
        $totalCount += getFileCount($file);
    }
    if(is_file($file))
    {
        $count++;  
    }  
}

function getFileCount($dir)
{
    global $subFileCount;
    if(is_dir($dir))
    {
        $subfiles = glob($dir.'/*');
        if(count($subfiles))
        {      
            foreach ($subfiles as $file) 
            {
                getFileCount($file);
            }
        }
    }
    if(is_file($dir))
    {
        $subFileCount++;
    }
    return $subFileCount;
}

$totalFilesCount = $count + $totalCount; 
echo 'Total Files Count ' . $totalFilesCount;

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Based on the accepted answer, here is a way to count all files in a directory RECURSIVELY:

iterator_count(
    new \RecursiveIteratorIterator(
        new \RecursiveDirectoryIterator('/your/directory/here/', \FilesystemIterator::SKIP_DOTS)
    )
)

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  simple code add for file .php then your folder which number of file to count its      

    $directory = "images/icons";
    $files = scandir($directory);
    for($i = 0 ; $i < count($files) ; $i++){
        if($files[$i] !='.' && $files[$i] !='..')
        { echo $files[$i]; echo "<br>";
            $file_new[] = $files[$i];
        }
    }
    echo $num_files = count($file_new);

simple add its done ....

참고URL : https://stackoverflow.com/questions/12801370/count-how-many-files-in-directory-php