문자열에서 숫자 제거

문자열에서 숫자 제거

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문자열에서 숫자를 제거하려면 어떻게해야합니까?

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이것이 귀하의 상황에 적합합니까?

>>> s = '12abcd405'
>>> result = ''.join([i for i in s if not i.isdigit()])
>>> result
'abcd'

이것은 목록 이해력을 사용하며 여기에서 일어나는 일은 다음 구조와 유사합니다.

no_digits = []
# Iterate through the string, adding non-numbers to the no_digits list
for i in s:
    if not i.isdigit():
        no_digits.append(i)

# Now join all elements of the list with '', 
# which puts all of the characters together.
result = ''.join(no_digits)

@AshwiniChaudhary 및 @KirkStrauser가 지적했듯이 실제로 한 줄에 괄호를 사용할 필요가 없으므로 괄호 안의 부분을 생성기 표현식으로 만듭니다 (목록 이해보다 효율적 임). 이것이 귀하의 과제에 대한 요구 사항에 맞지 않더라도 결국 읽어야 할 내용입니다 :) :

>>> s = '12abcd405'
>>> result = ''.join(i for i in s if not i.isdigit())
>>> result
'abcd'

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그리고 믹스에 던져 넣는 str.translate것은 반복 / 정규 표현식보다 훨씬 빠르게 작동하는 자주 잊혀진 것입니다.

Python 2 :

from string import digits

s = 'abc123def456ghi789zero0'
res = s.translate(None, digits)
# 'abcdefghizero'

Python 3 :

from string import digits

s = 'abc123def456ghi789zero0'
remove_digits = str.maketrans('', '', digits)
res = s.translate(remove_digits)
# 'abcdefghizero'

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선생님이 필터 사용을 허용하는지 확실하지 않지만 ...

filter(lambda x: x.isalpha(), "a1a2a3s3d4f5fg6h")

보고-

'aaasdffgh'

루핑보다 훨씬 효율적입니다 ...

예:

for i in range(10):
  a.replace(str(i),'')

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이것에 대해 :

out_string = filter(lambda c: not c.isdigit(), in_string)

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Just a few (others have suggested some of these)

Method 1:

''.join(i for i in myStr if not i.isdigit())

Method 2:

def removeDigits(s):
    answer = []
    for char in s:
        if not char.isdigit():
            answer.append(char)
    return ''.join(char)

Method 3:

''.join(filter(lambda x: not x.isdigit(), mystr))

Method 4:

nums = set(map(int, range(10)))
''.join(i for i in mystr if i not in nums)

Method 5:

''.join(i for i in mystr if ord(i) not in range(48, 58))

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I'd love to use regex to accomplish this, but since you can only use lists, loops, functions, etc..

here's what I came up with:

stringWithNumbers="I have 10 bananas for my 5 monkeys!"
stringWithoutNumbers=''.join(c if c not in map(str,range(0,10)) else "" for c in stringWithNumbers)
print(stringWithoutNumbers) #I have  bananas for my  monkeys!

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Say st is your unformatted string, then run

st_nodigits=''.join(i for i in st if i.isalpha())

as mentioned above. But my guess that you need something very simple so say s is your string and st_res is a string without digits, then here is your code

l = ['0','1','2','3','4','5','6','7','8','9']
st_res=""
for ch in s:
 if ch not in l:
  st_res+=ch

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If i understand your question right, one way to do is break down the string in chars and then check each char in that string using a loop whether it's a string or a number and then if string save it in a variable and then once the loop is finished, display that to the user

참고URL : https://stackoverflow.com/questions/12851791/removing-numbers-from-string